Solution:Total number of books in all three shelves = 140
Total number of books in C = 40
Let total number of books in shelf B = X
Then total number of books in shelf A = X + 6
So, X + X + 6 + 40 = 140
2X = 94
X = 47
So, shelf A contains 53 books and shelf B contains 47 books.
Given, number of books of English in shelf A is 20.
So, number of books of Maths in shelf A = 20 × 75/100 = 15
Therefore, number of books of English in shelf C = 15
And number of books of Hindi in shelf C = 15
Number of books of Maths in shelf C = 40 - (15 + 15) = 10
Now, number of books of Maths in shelf B = 15 - 3 = 12
And number of books of Hindi in shelf B = 15 - 5 = 10
Therefore, number of books of English in Shelf B
= 47 - (12 + 10) = 25
And number of books of Hindi in shelf A = 53 - (15 + 20) = 18
We can summarize all these information in a table as,
Shelf | Maths | English | Hindi | Total |
A | 15 | 20 | 18 | 53 |
B | 12 | 25 | 10 | 47 |
C | 10 | 15 | 15 | 40 |
Total | 37 | 60 | 43 | 140 |
Required Difference = 18 - 10 = 8