Algebra (Mathematics Chapterwise Solved Papers for Teaching) (Part-3)Theory of Equation and InequationsTotal Questions: 5011. Solve the following equation. [DSE TGT 2019](a) pqr(b) -q/r(c) pยฒ-2q(d) -p/rCorrect Answer: (b) -q/rSolution:12. The degree of polynomials is: [OAVS TGT 2018](a) the highest power of ๐(b) the lowest power of ๐(c) the smallest coefficient of ๐(d) the largest coefficient of ๐Correct Answer: (a) the highest power of ๐Solution:We know that the degree of polynomial is highest positive integer of power of variable. Hence, the degree of polynomial is the highest power of ๐.13. A root of an equation that does not satisfy the equation is called: [OAVS TGT 2018](a) Reflective root(b) Extraneous root(c) Square root(d) Complex rootCorrect Answer: (b) Extraneous rootSolution:Extraneous Root : An extraneous root is a root that is not a true solution to an equation.14. If bยฒ โ 4ac is > 0 and a perfect square, then the roots of a๐ยฒ + b๐ + c = 0 are: [OAVS TGT 2018](a) Imaginary(b) Equal(c) Rational(d) IrrationalCorrect Answer: (c) RationalSolution:We know ihat if bยฒ โ 4ac is > 0 and a perfect square, then roots of quadratic equation a๐ยฒ + b๐ +c = 0 will be rational.15. If bยฒ - 4ac < 0, then the roots of a๐ยฒ +b๐+c=0 are: [OAVS TGT 2018](a) Equal(b) Rational(c) Irrational(d) ImaginaryCorrect Answer: (d) ImaginarySolution:We know that if discriminant of quadratic eqn D = bยฒ - 4ac < 0 i.e. negative, then roots of quadratic equation will be imaginary.16. The solution set of the equation ๐ยฒ - 2๐+3 = 0 is: [OAVS TGT 2018](a) (1ยฑiโ2)(b) ยฑi(c) ยฑ1(d) ยฑiโ2Correct Answer: (a) (1ยฑiโ2)Solution:17. If ๐โด โ 3๐ + 5 is divided by 2๐ - 1, then the remainder is: [OAVS TGT 2018](a) 57/16(b) 3(c) 10(d) -9Correct Answer: (a) 57/16Solution:18. If ๐ยฒ - 1 is a factor of a๐โด + b๐ยณ + c๐ยฒ + d๐ +e, then: [OAVS TGT 2018](a) a+c+c=d+ะต(b) a+c+e=b+d(c) a+c+e=c+d(d) b+c+d =a+eCorrect Answer: (b) a+c+e=b+dSolution:19. If a polynomial p(๐) is divided by a linear division (๐ - b), then the remainder is: [OAVS TGT 2018](a) p (1)(b) p (2)(c) P (0)(d) p (b)Correct Answer: (d) p (b)Solution:If p(๐) is divided by a linear division (๐-b), then remainder will be p(b).20. The solution of 4๐ -3 > 6 is: [OAVS TGT 2018](a) ๐>2(b) ๐>(9/4)(c) ๐>(4/9)(d) ๐>1Correct Answer: (b) ๐>(9/4)Solution:Given 4๐-3> 6 Adding '3' both sides- โ 4๐ >9 โ ๐ >(9/4) is solution of above inequality.Submit Quiz« Previous12345Next »
