Algebra (Mathematics Chapterwise Solved Papers for Teaching) (Part-8)Theory of Equation and InequationsTotal Questions: 3311. If π, π and π are real and different, then the equation u= πΒ² +4πΒ² +9πΒ² +12ππ-4ππ -2ππ is always [TGT 2010](a) zero(b) non-negative(c) non-positive(d) None of theseCorrect Answer: (b) non-negativeSolution:12. If 1 is a root of equation aπΒ²+bπ+c=0, then- [TGT 2009](a) a = 1(b) b = 1(c) c = 1(d) a+b+c= 0Correct Answer: (d) a+b+c= 0Solution:If 1 is the root of the quadratic equation Β aπΒ²+bπ+c=0 then π = 1 will satisfy the equation. a.1Β² +b.1 +c = 0 β a+b+c = 013. If the quadratic equation pπΒ²-2π+2 = 0 has real linear factor, the value of p will be [TGT 2009](a)(b)(c)(d)Correct Answer: (a)Solution:14. If eΛ£ = y+β(1+yΒ²), the y = [TGT 2009](a)(b)(c)(d)Correct Answer: (b)Solution:15. The number of root of the quadratic equation 8secΒ²ΞΈ - 6secΞΈ +1 = 0 will be [TGT 2009](a) Infinite(b) 1(c) 2(d) 0Correct Answer: (d) 0Solution:16. If one root of equation aπΒ² + bπ + c = 0 is square of another root then- [TGT 2009](a) aΒ³+bc (b+c) = 3abc(b) bΒ³+ac (a+c) = 3abc(c) cΒ³+ab (a+b) = 3abc(d) None of theseCorrect Answer: (b) bΒ³+ac (a+c) = 3abcSolution: 17. If tanΞ± and tanΞ² are roots of quadratic equation πΒ²- pπ + q = 0. Then the value of sinΒ²(Ξ±+Ξ²) will be; [TGT 2009](a)(b)(c)(d)Correct Answer: (a)Solution:18. The difference of roots of quadratic equation πΒ²-6π+6=0 is- [TGT 2005](a) 0(b) β6(c) β12(d) β18Correct Answer: (c) β12Solution:19. In a quadratic equation πΒ²+pπ+q = 0, taken coefficient of π 17 instead of 13 by which obtained roots are β2 & β15. Therefore, what is orginal roots of the equation? [TGT 2005](a) 2, 15(b) 10, 3(c) -10, -3(d) -2, 15Correct Answer: (c) -10, -3Solution:20. If π is real and K=(πΒ²-x+1)/πΒ²+π+1, then [TGT 2005](a)(b)(c)(d)Correct Answer: (a)Solution: Submit Quiz« Previous1234Next »