Algebra (Mathematics Chapterwise Solved Papers for Teaching) (Part-9)Sequences and Series (A.P, G.P, H.P)Total Questions: 501. In a G.P. consisting of positive terms, each term equals the sum of the next two terms. Then, the common ratio of this progression equals : [EMRS PGT-2023](a)(b)(c)(d)Correct Answer: (a)Solution:2. In an A.P.Sₙ, denotes the sum of first n terms. If S₂ₙ =3.Sₙ, then S₃ₙ : Sₙ is equal to : [EMRS PGT-2023](a) 5:1(b) 6:1(c) 8:1(d) 4:1Correct Answer: (b) 6:1Solution:3. The sum of first three terms of a GP is 21/4 are their product is 27/8. The common ratio of the G.P. is: [EMRS PGT-2023](a)(b)(c)(d)Correct Answer: (a)Solution:4. The value of series 1²+2²+3² +...+p² is [Bihar (TRE 2.0)-2023](a)(b)(c)(d)(e)Correct Answer: (c)Solution:5. If 1/(b+c), 1/(c+a) and 1/(a+b) are in arithmetic progression, then [Bihar (TRE 2.0)-2023](a) a, b, c are in arithmetic progression(b) a², b², c² are in arithmetic progression(c) 1/a, 1/b, 1/c are in arithmetic progression(d) More than one of the above(e) None of the aboveCorrect Answer: (b) a², b², c² are in arithmetic progressionSolution:6. The first term of a geometric progression is 1. If the sum of the third term and fifth term is 90, then the common ratio of the geometric progression is [Bihar (TRE 2.0)-2023](a) 3(b) 2(c) 1(d) More than one of the above(e) None of the aboveCorrect Answer: (a) 3Solution:7. Which term of the following sequence is 128? [Bihar (TRE 2.0)-2023]2,2 √2, 4, .....(a) 9th term(b) 12th term(c) 13th term(d) More than one of the above(e) None of the aboveCorrect Answer: (c) 13th termSolution:8. If the arithmetic mean and geometric mean of the roots of a quadratic equation are 8 and 5, respectively, then the quadratic equation is [Bihar (TRE 2.0)-2023](a) 𝓍²- 13𝓍+40= 0(b) 𝓍²- 16𝓍 +25 = 0(c) 𝓍²- 13𝓍+25 = 0(d) More than one of the above(e) None of the aboveCorrect Answer: (b) 𝓍²- 16𝓍 +25 = 0Solution:9. Solve the following equation? [EMRS TGT-2023](a) mnq(b) q³(c) (m +n)q²(d) q³/2Correct Answer: (b) q³Solution:10. If the roots of the equation 𝓍³-12𝓍²+39𝓍-28 = 0 are in AP, then their common difference is: [EMRS TGT-2023](a) ±2(b) ±3(c) ±4(d) ± 1Correct Answer: (b) ±3Solution:Submit Quiz12345Next »