BANK & INSURANCE (ALPHANUMERIC SERIES) PART 1

Total Questions: 385

71. Directions (71-75): Study the following arrangement and answer questions given:

67719241564923412585848312752673953

Ques : How many such 7’s is there in the above arrangement each of which is immediately followed by a digit which has a numerical value of more than four?

Correct Answer: (c) Two
Solution:

7’s after which number came of value more than 4.

72. How many such 1’s is there in the above arrangement each of which is immediately preceded by a perfect square?

Correct Answer: (c) Two
Solution:1’s before which perfect square came

73. How many such 9’s is there in the above arrangement each of which is immediately preceded and followed by an odd digit?

Correct Answer: (b) One
Solution:pattern is O9O

74. How many such 5’s is there in the above arrangement each of which is immediately followed by a digit which has a numerical value of more than itself?

Correct Answer: (d) Three
Solution:5’s after which number comes of value more than 5.

75. How many such 2’s is there in the above arrangement each of which is immediately followed by an odd number and immediately preceded by an even number?

Correct Answer: (a) None
Solution:pattern is E2O

76. Directions (76-80): Study the following arrangement and answer questions given:

76355298713685742569871236479864

Ques : How many such even numbers are there which are immediately followed by an even number and immediately preceded by an odd number?

Correct Answer: (d) More than three
Solution:pattern is OEE

77. How many such odd numbers which are immediately preceded by and followed by a prime number?

Correct Answer: (d) Four
Solution:pattern is POP

78. All the even number which are immediately followed by a prime number are dropped from the string, then which number will be the 11th from the left end?

Correct Answer: (a) 5
Solution:5

79. If the last 15 numbers are reversed, then which number is 21st from the left end?

Correct Answer: (d) 9
Solution:

total numbers are 32 means first 17 will remain at their same position so 17+5=21 for that take the 5th element from right side of the series which will become 21st from left side when reversed last 15 numbers.

80. If all the number which comes at odd position from the left end are dropped from the series, then how many numbers are left in the series?

Correct Answer: (d) 16
Solution:

since total numbers are 32 so numbers at even position will be 16