Solution:Total distance travelled by bus A on Monday = 450 Km
Distance travelled by bus A on Monday with high speed = 5/9 × 450 = 250 Km
Distance travelled by bus A on Monday with low speed = 4/9 × 450 = 200 Km
Similarly, we can calculate for all the buses and for both the days, as in the following table:
Buses | Total distance travelled on Monday (in Km) | Total distance travelled on Tuesday (in Km) |
A | 450 | 600 |
B | 540 | 400 |
C | 620 | 440 |
D | 480 | 560 |
E | 520 | 540 |
Buses | Monday High Speed (in Km) | Monday Low Speed (in Km) | Tuesday High Speed (in Km) | Tuesday Low Speed (in Km) |
A | 5/9 × 450 = 250 | 4/9 × 450 = 200 | 7/12 × 600 = 350 | 5/12 × 600 = 250 |
B | 4/9 × 540 = 240 | 5/9 × 540 = 300 | 11/20 × 400 = 220 | 9/20 × 400 = 180 |
C | 16/31 × 620 = 320 | 15/31 × 620 = 300 | 6/11 × 440 = 240 | 5/11 × 440 = 200 |
D | 7/12 × 480 = 280 | 5/12 × 480 = 200 | 3/8 × 560 = 210 | 5/8 × 560 = 350 |
E | 7/13 × 520 = 280 | 6/13 × 520 = 240 | 4/9 × 540 = 240 | 5/9 × 540 = 300 |
96. (d): Distance travelled by bus A with high speed on Monday = 250 Km
Distance travelled by bus A with high speed on Tuesday = 350 Km
Distance travelled by bus C with low speed on Monday = 300 Km
Distance travelled by bus C with low speed on Tuesday = 200 Km
Required ratio = (250 + 350) : (300 + 200)
= 600 : 500 = 6 : 5