BANK & INSURANCE (DATA INTERPRETATION) PART 3

Total Questions: 129

121. What percent of total battery capacity of earphone R is already charged?

Correct Answer: (a) 13.33 min 
Solution:

Charge rate of battery of earphone P = 0.2 mAh/seconds

Remaining part of battery of earphone P that is yet to be charged = 160 mAh

Time taken to charge the remaining battery of that earphone = 160/0.2 = 800 seconds = 13.33 min

122. What part of total battery capacity of earphone T is not charged?

Correct Answer: (d) 66.67% 
Solution:

Total battery capacity of earphone R = 150 mAh

Total battery capacity of earphone R which is already charged = 100 mAh

Required percent = (100/150) × 100 = 66.67%

123. If playback rate of earphone Q is 5 min/mAh, then for how long earphone Q will work with its charged battery capacity?

Correct Answer: (b) 20 hours 
Solution:

Playback rate of earphone Q = 5 min/mAh
Charged battery capacity of earphone Q = 240 mAh
Total time for which earphone Q will work with its charged battery capacity = 240 × 5 = 1200 min
= 20 hours

124. What part of total battery capacity of earphone T is not charged?

Correct Answer: (e) 1/6
Solution:Total battery capacity of earphone T = 360 mAh
Total battery capacity of earphone T which is not charged = 60 mAh
Required fraction = 60/360 = 1/6

125. Directions (125-129): Refer the following graph carefully and answer the question accordingly.

Below line graph shows the information about the percentage of students passed out of total students from two tuition classes A and B in four different years.

Year

Number of students in tuition class A

Number of students in tuition class B

2017

360

250

2018

500

600

2019

440

700

2020

540

300

Ques: In tuition class B in year 2018, Boys and girls are in the ratio of 7:5. Calculate the total number of girls failed in 2018 from tuition class B, If ratio of number of passed boys to passed girls is 6:5.

Correct Answer: (b) 100 
Solution:

Year

Percentage of passed students from tuitions A

Percentage of passed students from tuitions B

2017

65%

80%

2018

80%

55%

2019

75%

70%

2020

90%

85%

Year

Number of students in tuitions classes A

Passed students from tuitions A

Number of students in tuitions classes B

Passed students from tuitions B

2017

360

234

250

200

2018

500

400

600

330

2019

440

330

700

490

2020

540

486

300

255

Total number of students in 2018 from tuition class B = 600

Boys and girls are in the ratio of 7:5

Total Boys = (7/12) × 600 = 350
Total girls = (5/12) × 600 = 250

Total passed students = (55/100) × 600 = 330

Ratio of passed boys to passed girls = 6:5

Total girls passed in the 2018 from tuition class B = (5/11) × 330 = 150

Total girls failed in the 2018 from tuition class B
= 250 - 150 = 100

126. Calculate the average of passed students from tuition class A in year 2017, passed students from tuition classes B in year 2018, passed students from tuition class B in year 2019, and passed students from tuition class B in year 2020.

Correct Answer: (c) 385 
Solution:

Total number of passed students from tuition class A in year 2017 = 234

Total number passed students from tuition class B in year 2018 = 330

Total number passed students from tuition class B in year 2019 = 490

Total number passed students from tuition class A in year 2020 = 486

Average = (234 + 330 + 490 + 486)/4
= (1540/4) = 385

127. Calculate the total failed students from tuition class A in year 2017, tuition class B in year 2018, tuition class A in year 2020 and tuition class B in year 2019.

Correct Answer: (a) 660 
Solution:

Total failed students from tuition class A in year 2017 = 360 - 234 = 126

Total failed students from tuition class B in year 2018 = 600 - 330 = 270

Total failed students from tuition class A in year 2020 = 540 - 486 = 54

Total failed students from tuition class B in year 2019 = 700 - 490 = 210

Total = 126 + 270 + 54 + 210 = 660

128. What is the ratio of difference between passed students from tuition class B in year 2019 and passed students from tuition class A in year 2018 to the difference between passed students from tuition class A in year 2019 and passed students from tuition class B in year 2020?

Correct Answer: (d) 6:5 
Solution:

Passed students from tuition class B in year 2019 = 490

passed students from tuition class A in year 2018 = 400

difference = 490 - 400 = 90

passed students from tuition class A in year 2019 = 330

passed students from tuition class B in year 2020 = 255

difference = 75

required ratio = 90:75 = 6:5

129. Calculate the average of failed students from tuition class B in year 2017, failed students from tuition class A in year 2018, failed students from class A in year 2019, and failed students from tuition class B in year 2020.

Correct Answer: (d) 76.25 
Solution:

Failed students from tuition class B in year 2017
= 250 - 200 = 50

Failed students from tuition class A in year 2018
= 500 - 400 = 100

Failed students from tuition class A in year 2019
= 440 - 330 = 110

Failed students from tuition class B in year 2020
= 300 - 255 = 45

Required Average = (50 + 100 + 110 + 45) / 4 = 76.25