Solution:Let the number of laptops and number of coolers sold by shopkeeper A be 4t and 6t respectively.
Number of laptops sold by shopkeeper B = 6t + 20
Number of televisions sold by shopkeeper B = (3/2) × 6t = 9t
Number of coolers sold by shopkeeper B = 80 (given)
ATQ, (6t + 20) + 9t + 80 = 400
=> 15t + 100 = 400
=> 15t = 300
=> t = (300/15) = 20 ........(1)
Let the number of televisions sold by shopkeeper A be ‘y’
Total number of items sold by shopkeeper A = 700 - 400 = 300
ATQ, 4t + 6t + y = 300
=> 10t + y = 300 ........(2)
Putting the value of t from equation (1) to (2), we get:
=> 200 + y = 300
=> y = 100
Shopkeeper | Number of laptops sold | Number of televisions sold | Number of coolers sold | Total items sold
A → 80 | 100 | 120 | 300
B → 140 | 180 | 80 | 400
Total items sold by shopkeeper A = 80 + 100 + 120 = 300
Total items sold by shopkeeper B = 140 + 180 + 80 = 400
Total items sold by shopkeeper A = 300
Number of televisions sold by shopkeeper B = 180
Hence, required ratio = 300:180 = 5:3