BANK & INSURANCE (IBPS PO PRELIMS 2025) MOCKTEST 5

Total Questions: 35

1. Directions (1-4): In each question two equations number (I) and (II) are given. You should solve both the equations and mark appropriate answer.

I. x² − 10x + 24 = 0   II. 5y² − 16y + 12 = 0

Correct Answer: (b) If x > y
Solution:

x² - 6x - 4x + 24 = 0
x(x-6) - 4(x-6) = 0
(x-4)(x-6) = 0
x = 4 & 6

II.
5y² - 10y - 6y + 12 = 0
5y(y-2) - 6(y-2) = 0
(5y-6)(y-2) = 0
y = 6/5 & 2

y = 1.2 & 2

x

y

Relation

4

1.2

x > y

4

2

x > y

6

1.2

x > y

6

2

x > y

So, x > y

2. I. 2x² − 9x + 10 = 0   II. y² − 12y + 35 = 0

Correct Answer: (c) If x < y
Solution:

I.
2x² - 4x - 5x + 10 = 0
2x(x-2) - 5(x-2) = 0
(2x-5)(x-2) = 0
x = 5/2 & 2

x = 2.5 & 2

II.
y² - 7y - 5y + 35 = 0
y(y-7) - 5(y-7) = 0
(y-7)(y-5) = 0
y = 7 & 5

x

y

Relation

2.5

7

y > x

2.5

5

y > x

2

7

y > x

2

5

y > x

So, x < y

3. I. 6x² − 7x + 2 = 0   II. 10y² − 11y + 3 = 0

Correct Answer: (a) If x = y or no relation can be established
Solution:

I.
6x² - 4x - 3x + 2 = 0
2x(3x-2) - 1(3x-2) = 0
(2x-1)(3x-2) = 0
x = 1/2 & 2/3

x = 0.5 & 0.66

II.
10y² - 6y - 5y + 3 = 0
2y(5y-3) - 1(5y-3) = 0
(2y-1)(5y-3) = 0
y = 1/2 & 3/5

y = 0.5 & 0.60

x

y

Relation

0.5

0.5

y = x

0.5

0.60

y > x

0.66

0.5

x > y

0.66

0.6

x > y

So, no relation can be established

4. I. 2x² + 19x + 42 = 0  II. 2y² + 7y + 5 = 0

Correct Answer: (c) If x < y
Solution:

I.
2x² + 12y + 7y + 42 = 0
2x(x+6) + 7y(y+6) = 0
(2x+7y)(y+6) = 0
x = -7/2 & -6
x = -3.5 & -6

II.
2y² + 2y + 5y + 5 = 0
2y(y+1) + 5(y+1) = 0
(2y+5)(y+1) = 0
y = -5/2 & -1
y = -2.5 & -1

x

y

Relation

-3.5

-2.5

y > x

-3.5

-1

y > x

-6

-2.5

y > x

-6

-1

y > x

So, x < y

5. Directions (5-8): What approximate value come in the place of ‘x’ in the following questions.

779.23/13 + 4.98 + 23 = x% of 60.03

Correct Answer: (d) 147 
Solution:

780/13 + 5 + 23 = x/100 × 60
60 + 5 + 23 = x × 3/5
88 × 5
x = ———
3
x = 146.66 ≈ 147

6. 39.98% of 249.99 + √196.04 = x² + 55.93

Correct Answer: (d) 8 
Solution:40/100 × 250 + 14 = x² + 56
100 + 14 = x² + 56
x² = 58
x ≈ 8

7. 20.99² − 24.97% of 220.02 ÷ ? = 131.13

Correct Answer: (c) 255
Solution:21² - 25/100 × 220 - ? = 131
441 - 55 - ? = 131
? = 386 - 131
? = 255

8. 24² + 12 = ? × (50% of 56) ⇒ 576 + 12 = ? × 28 ⇒ ? = 588/28 = 21

Correct Answer: (c) 21
Solution:24² + 12 = ? × (50% of 56)
⇒ 576 + 12 = ? × 28
⇒ ? = 588/28 = 2124² + 12 = ? × (50% of 56)

⇒ 576 + 12 = ? × 28
⇒ ? = 588/28 = 21

9. Directions (9-14): The table given below shows the total number of red and blue balls in five different bags (A, B, C, D & E). It also shows the difference between red and blue balls and percentage of red balls with respect to total balls

Total bags

Difference between red and blue balls

Percentage of red balls with respect to total balls

A

60

62.5%

B

198

66.5%

C

188

70%

D

76

60%

E

330

72%

Ques : The number of red balls in A and E together is what percentage of number of blue balls in A and E together?

Correct Answer: (b) 220 
Solution:

Percentage of blue balls = 100 – 62.5 = 37.5%
(62.5 – 37.5)% = 60
25% = 60
100% = 240
Red balls = 62.5% of 240 = 150
Blue balls = 240 – 150 = 90

Similarly,

Total bags

Total balls

Red balls

Blue balls

A

240

150

90

B

600

399

201

C

470

329

141

D

380

228

152

E

750

540

210

Required answer =
(150 + 540) / (90 + 210) × 100 = 230%

10. The sum of number of blue balls in B and number of red balls in C are how many less than number of red balls in E?

Correct Answer: (c) 50
Solution:

Required answer = 540 – (210 + 392) = 10