BANK & INSURANCE (IBPS RRB PO PRELIMS 2025) MOCKTEST 7

Total Questions: 40

11. If the cost of each shirt is Rs 24 and the cost of each trousers is 25% more than the shirts. Find the revenue (in Rs.) generated by A from selling all the items.

Correct Answer: (a) 6900  
Solution:Cost of shirts = 24
Cost of trousers = 30
Required answer = 24 × 100 + 150 × 30 = Rs. 6900

12. If the ratio of defective and non-defective items manufactured by B is 1:4 and 20% of the items sold are defectives, find the difference between unsold defective items and sold non-defective items.

Correct Answer: (a) 156  
Solution:

Let defective and non-defective items manufactured by B be 1x and 4x respectively.
ATQ, 5x = 245
⇒ 49 = x

Defective items manufactured = 1x = 49
Non-defective items manufactured = 4x = 196

Defective items sold = 20% of 205 = 41
Non-defective items sold = 205 − 41 = 164

Defective items unsold = 49 − 41 = 8
Non-defective items unsold = 196 − 164 = 32

Required answer = 164 − 8 = 156

13. Directions (53-58): Read the following line graph carefully and answer the questions given below. The graph shows the number of items A and items B sold in four months.

(Graph showing months: March, April, May, June; Legend: A and B)

Ques : If out of the total item B sold in March and April together, 50% are red, 25 are black, and the rest are green in colour, then find the number of green items B sold by in March and April together.

Correct Answer: (d) 240  
Solution:Required answer = (330 + 200) − (330 + 200) × 50/100 − 25
= 530 − 265 − 25 = 240

14. Find the difference between the total number of item A sold in April and May together and the number of items B sold in March

Correct Answer: (a) 80  
Solution:Required difference = 250 + 160 − 330 = 80

15. Total number of item B sold in May is what per cent more or less than that of in April?

Correct Answer: (a) 10%  
Solution:Required answer = (200 − 180) / 200 × 100 = 10%

16. If the number of item A sold in July are 40% more than that of in May and out of which 3/4th are defective items A. If in July sold defective item A in Rs.5, then find the total revenue collected in July selling all defective item A.

Correct Answer: (e) Rs 840
Solution:Item A sold in July = 140% of 160 = 224
Defective item A = 3/4 of 224 = 168
Required answer = 5 × 168 = Rs 840

17. Find the ratio of the total number of item A and B together sold in March to the total number of items A and B together sold in May

Correct Answer: (e) None of these
Solution:Required ratio = 320 + 330 : 160 + 180
= 650 : 340 = 65 : 34

18. The total items A and B sold in the month of June is what percentage of items A sold in the month of April?

Correct Answer: (a) 164%  
Solution:

Required answer = (200 + 210) / 250 × 100 = 164%

19. The speed of a boat in still water is 20 km/hr and the ratio of downstream to upstream speed of the boat is 5 : 3 respectively. Find the time taken by the boat to cover 240 km downstream (in hours).

Correct Answer: (c) 9.6
Solution:

Speed in still water = 20 km/hr
Distance downstream = 240 km
Ratio of downstream to upstream speed = 5 : 3

Let downstream speed = 5x and upstream speed = 3x

Speed in still water = (Downstream + Upstream) / 2

Then, speed in still water = (5x + 3x)/2 = 8x/2 = 4x
Given 4x = 20 ⇒ x = 5
So downstream speed = 5x = 5 × 5 = 25 km/hr
Time taken to cover 240 km downstream = Distance / Speed = 240 / 25 = 9.6 hours

20. A vessel contains milk and water in the ratio 5 : 3, respectively. If 16 liters of the mixture are taken out and 4 liters of water are added, the ratio of milk to water becomes 3 : 2. Find the initial quantity of milk (in liters).

Correct Answer: (a) 70  
Solution:

Let total initial quantity = x liters

Quantity of Milk = 5/8 x liters

Quantity of Water = 3/8 x liters

16 liters removed in 5:3

⇒ Milk removed = 5/8 × 16 = 10 liters

⇒ Water removed = 16 − 10 = 6 liters

Remaining milk = 5/8 x − 10

Remaining water = 3/8 x − 6 + 4 = 3/8 x − 2

ATQ,

(5x/8 − 10) / (3x/8 − 2) = 3/2

2 × (5x/8 − 10) = 3 × (3x/8 − 2)

(10x/8 − 20) = (9x/8 − 6)

10x − 160 = 9x − 48

x = 112

Initial quantity of milk = (5/8) × 112 = 70 liters