BANK & INSURANCE (RATIO AND PROPORTION) PART 1

Total Questions: 70

51. What is the difference between A’s and B’s shares?

Correct Answer: (b) Rs. 2,928
Solution:

Required difference = Rs. [(7 − 3) / 15] × 10980 = Rs. 2928

52. A sum of Rs. 221 is divided among X, Y and Z such that X gets Rs. 52 more than Y, Y gets Rs. 26 more than Z. The ratio of the shares of X, Y and Z respectively is

Correct Answer: (a) 9:5:3
Solution:

221 is divided among X, Y and Z.

Y gets Rs. (Z + 26)
X gets Rs. (Z + 26 + 52) = Rs (Z + 78)

According to question

Z + 78 + Z + 26 + Z = 221

⇒ 3Z + 104 = 221

⇒ Z = 117/3

⇒ Z = 39

X = 39 + 78 = 117
Y = 39 + 26 = 65
Z = 39

117 : 65 : 39 = 9 : 5 : 3

53. If 50% of a certain number is equal to 3/4th of the another number, what is the ratio between the number?

Correct Answer: (a) 3:2
Solution:

Let the one number be x and another number y

Then, 50% of x = 3y/4

⇒ 50 × x/100 = 3y/4

⇒ x/y = 3/2 = 3 : 2

54. Ratio of the earning of A and B is 4 : 7 respectively. If the earnings of A increase by 50% and the earnings of B decrease by 25%, the new ratio of their earnings becomes 8:7 respectively. What are A’s earnings?

Correct Answer: (d) Data inadequate
Solution:

Let the original earnings of A and B be Rs. 4x and Rs. 7x

New earnings of A = 150% of Rs. 4x = (150/100 × 4x) = Rs. 6x

New earnings of B = 75% of Rs. 7x = (75/100 × 7x)

= Rs. 21x/4

6x : 21x/4 = 8 : 7

This does not give x. So, the given data is inadequate.

55. The cost of making an article is divided between materials, labour and overheads in the ratio of 3:4:1.If the material costs Rs. 234, then the labour cost?

Correct Answer: (b) Rs. 312
Solution:

Cost of making is divided among material : labour : overheads = 3 : 4 : 1

Total material cost = Rs. 234

3x = 234

⇒ x = 78

⇒ Labour cost = 4 × 78 = Rs. 312

56. The ages of Mira, Tina and Sania are in the ratio of 6 : 4 : 7 respectively. If the sum of their ages is 34 years, what is Sania's age?

Correct Answer: (e) None of these
Solution:

Ratio of the ages of Mira, Tina and Sania = 6 : 4 : 7

Let their age be 6x : 4x : 7x

According to the question,

6x + 4x + 7x = 34

⇒ 17x = 34

⇒ x = 2

Sania age = 7x = 7 × 2 = 14 yr.

57. In a school the number of boys and that of the girls are in the respective ratio of 2:3. If the number of boys is increased by 20% and that of girls is increased by 10%, what will be the new ratio of number of boys to that of the girls?

Correct Answer: (e) None of these
Solution:

Ratio of boys and girls in the school = 2 : 3

New, increased value = 2 × 120/100 : 3 × 110/100

= 240 : 330

⇒ 24 : 33 = 8 : 11

58. When x is subtracted from the numbers 9, 15 and 27, the remainders are in continued proportion. What is the value of x?

Correct Answer: (e) None of these
Solution:

From the given question:

(9 − x)/(15 − x) = (15 − x)/(27 − x)

⇒ (15 − x)² = (9 − x)(27 − x)

⇒ 225 − 30x + x² = 243 + x² − 36x

⇒ 6x = 18

⇒ x = 3

59. The price of sugar is increased by 20%. If the expenditure is not allowed to increase, the ratio between the reduction in consumption and the original consumption is:

Correct Answer: (c) 1:6
Solution:

Let the price of sugar was Rs. x per kg

After increase in price, new price per kg

= x + x × 20/100 = 6x/5

For Rs. 6x/5 we get 1 kg of sugar

For Rs. 1 we get 5/6x kg of sugar

For Rs. x we get 5/6 kg of sugar

Decrease in consumption of sugar

= 1 − 5/6 = 1/6

So, the required ratio = 1/6 : 1 = 1/6

60. The ratio of the number of boys to the number of girls in a school of 640 students is 5:3. If 30 more girls are admitted in the school, then how many more boys should be admitted so that the ratio of boys to that of the girls becomes 14:9.

Correct Answer: (d) 20
Solution:

Total students in school = 640

Ratio of number of boys to girls is 5 : 3 = 8 units in total

8 units = 640
1 unit = 80

Boys are 5 units = 400
Girls are 3 units = 240

On adding 30 more girls, Total girls = 270

Let x boys be added to make ratio of boys to girls 14 : 9

(400 + x)/270 = 14/9

⇒ x = 20