BANK & INSURANCE (SBI CLERK PRELIMS 2025) MOCKTEST 4

Total Questions: 50

1. Directions (1-4): The table given below show total number of fruits (Apples & Mangoes) sold by three shops and the ratio of apples to mangoes sold by these three shops. Read the data carefully and answer the questions given below.

Note: The difference between mangoes and apples sold by shops A is 16.

Ques: Find the difference between total number of mangoes sold by shops A & C together and total number of apples sold by shops A & B together.

Correct Answer: (e) 97
Solution:

For shop A, Sold mangoes = sold apples + 16
So, sold mangoes = (80 + 16) / 2 = 48
And, sold apples = 80 − 48 = 32

32 / 48 = p / (p + 1)
2p + 2 = 3p

For shop B, sold apples = 50 × 3/10 = 15
Sold mangoes = 50 − 15 = 35

For shop C, 0.5 : 2 = 1 : 4
Sold apples = 120 × 1/5 = 24
Sold mangoes = 120 − 24 = 96

Total number of mangoes sold by shops A & C
= 48 + 96 = 144

Total number of apples sold by shops A & B
= 32 + 15 = 47

Required difference = 144 − 47 = 97

2. The average number of apples sold by A, C and D is 32. If the ratio of total number of apples to mangoes sold by D is p : q and total mangoes sold by D are 5/8 th of total mangoes sold by C, then find the value of ‘q’.

Correct Answer: (b) 3 
Solution:

Total apples sold by A, C and D = 32 × 3 = 96
Total apples sold by D = 96 − (32 + 24) = 40

Total mangoes sold by D = 96 × 5/8 = 60

ATQ
40 / 60 = 2 / q
⇒ 20q = 60
⇒ q = 3

3. 3. Shop C sold 40% of total available fruits (Apples & Mangoes) and the ratio of total unsold mangoes to sold mangoes by shop C is 5 : p+2, then find the total unsold apples by shop C is what per cent of more than total sold mangoes by shop A?

Correct Answer: (e) 25%
Solution:

Total fruits available (Apples & Mangoes)
= 120 × (100 / 40) = 300

Unsold mangoes by shop C = 96 × (5 / (2+2)) = 120

Total unsold fruits (Apples & Mangoes) by shop C
= 300 − 120 = 180

Total unsold apples by shop C = 180 − 120 = 60

Required % = (60 − 48) / 48 × 100 = 25%

4. Shops C purchased each apple and mango at Rs 10 & Rs. 15, and he sold all fruits at profit of 40%. Find the total profit of received by C (C sold all purchased fruits).

Correct Answer: (c) 672 Rs.
Solution:

Total cost price of all apples and mangoes sold by C
= 24 × 10 + 96 × 15 = Rs. 1680

Total selling price of all apples and mangoes sold by C
= 1680 × (140 / 100) = Rs. 2352

Required profit = 2352 − 1680 = Rs. 672

5. Directions (5-9): Read the following pie chart carefully and answer the questions given below. The pie chart shows the percentage distribution of total students (boys and girls) in five different schools.

Ques: The total number of students in schools B and D together is what percentage more or less than the total number of students in school E?

Correct Answer: (e) 50%
Solution:

We have 100% = (22 + 17 + X + 3 + X + 8 + 2X)%
⇒ 100 = 50 + 4X
⇒ 50 = 4X
⇒ X = 12.5

The total students in A = 8000 × (22 / 100) = 1760
The total students in B = 8000 × (17 / 100) = 1360
The total students in C = 8000 × ((12.5 + 8) / 100) = 1240
The total students in D = 8000 × ((12.5 + 8) / 100) = 1640
The total students in E = 8000 × (2 × 12.5 / 100) = 2000

The total number of students in schools B and D together
= (1360 + 1640) = 3000

Required percentage = (3000 − 2000) / 2000 × 100 = 50%

6. The difference between the total number of boys and girls in school C is 170 (boys < girls). If the total number of boys in school B is 230 more than that of school C, then find the ratio of boys to girls in school B.

Correct Answer: (d) 9:7 
Solution:

Let the number of boys in C be g
And the number of girls in C = g + 170

Given, g + g + 170 = 1240
⇒ 2g = 1070
⇒ g = 535

The number of boys in C = 535
And the number of girls in C = 535 + 170 = 705

The number of boys in B = 230 + 535 = 765
The number of girls in B = 1360 − 765 = 595

Required ratio = 765 : 595 = 9 : 7

7. The total number of students in school F is 25% more than that in C. The ratio of the number of boys to the number of girls in school F is 19:12. If the number of girls in schools F and E together is 1935, then find the difference between the number of boys in schools E and F.

Correct Answer: (a) 285 
Solution:

The total number of students in school F
= 1.25 × 1240 = 1550

The number of boys in school F = 1550 × (19 / 31) = 950
The number of girls in school F = 1550 − 950 = 600

The number of girls in school E = 1935 − 600 = 1335
The number of boys in school E = 2000 − 1335 = 665

Required difference = 950 − 665 = 285

8. 25% of the total number of students in school A who participated in dance, and the rest participated in chess. The number of students who participated in chess in school E is 40 more than half of the students who participated in chess in school A. Find the average number of students who participated in dance.

Correct Answer: (e) 870
Solution:

The number of students in school A who participated in dance
= (25 / 100) × 1760 = 440

The number of students in school A who participated in chess
= 1760 − 440 = 1320

The number of students in school E who participated in chess
= 40 + (1320 / 2) = 700

The number of students in school E who participated in dance = 200 − 700 = 1300
Required average = (440 + 1300) / 2 = 870

9. Find the central angle corresponding to the total number of students in B and D together (in degree

Correct Answer: (d) 135 
Solution:

Required central angle = [{17+(12.5+8)}/100]×360 = 135

10. Two roots of the equation x² − Px + 84 = 0 are ‘a’ and ‘b’, and a − b = 5.

Quantity I: Value of 2P
Quantity II: Value of b² − a + 1

Correct Answer: (e) Quantity I = Quantity II or no relation
Solution:

Only root of 84 which follow a-b = 5 are 12 and 7
So, equation, x² − 19x + 84 = 0
So, P = 19

Quantity I: 2 × 19 = 38
Quantity II: 7² − 12 + 1 = 49 − 12 + 1 = 38
So, Quantity I = Quantity II