BANK & INSURANCE (SBI CLERK PRELIMS 2025) MOCKTEST 4

Total Questions: 50

11. A bag contains x black marbles, x+10 white marbles and x+20 yellow marbles. The probability of drawing one white marble randomly is 1/6 more than probability of drawing one black marble randomly.

Quantity I: Total number of yellow marbles in the bag.
Quantity II: 40

Correct Answer: (b) Quantity I < Quantity II
Solution:

ATQ,
x+103x+30=x3x+30+16\frac{x+10}{3x+30} = \frac{x}{3x+30} + \frac{1}{6}3x+30x+10​=3x+30x​+61​

⇒ 103x+30=16\frac{10}{3x+30} = \frac{1}{6}3x+3010​=61​
⇒ 60 = 3x + 30
⇒ x = 10

Quantity I: Total number of yellow marbles in the bag = 10 + 20 = 30
Quantity II: 40
So, Quantity I < Quantity II

12. Directions (12-14): There are two series I and II given below, and both series follows the same pattern. Find the missing terms of series II and answer the following questions.

Ques :  Which of the following statement/s is or are definitely true?
(i) 9² + 1 = R + S
(ii) 2Q = P + S/4
(iii) 2P/15 = S

Correct Answer: (e) Only i and iii
Solution:

Pattern of series I:
386 ÷ 2 + 1 = 194
194 ÷ 2 + 1 = 98
98 ÷ 2 + 1 = 50
50 ÷ 2 + 1 = 26
26 ÷ 2 + 1 = 14
14 ÷ 2 + 1 = 8

Series II:
834 ÷ 2 + 1 = 418
P = 418 ÷ 2 + 1 = 210
Q = 210 ÷ 2 + 1 = 106
R = 106 ÷ 2 + 1 = 54
S = 54 ÷ 2 + 1 = 28
28 ÷ 2 + 1 = 15


For (i) 81 + 1 = 54 + 28
⇒ 82 = 82 (it is true)

For (ii) 2 × 106 < 210 + 28/4
⇒ 212 < 217 (it is false)

For (iii) 2×21015=28\frac{2×210}{15} = 28152×210​=28
⇒ 28 = 28 (it is true)

So, only I and III are true.

13. Find the 50% of Q + R.

Correct Answer: (d) 107 
Solution:

Required answer = 50% of Q + R
= 1/2 × 106 + 54
= 53 + 54
= 107

14. Which of the following statement/s is or are definitely true?

(i) Sum of P and R is odd number
(ii) Sum of P and R is completely divisible by 4
(iii) Sum of R and S is less than 4th term of series I

Correct Answer: (c) Only ii
Solution:For (i) 210 + 54 = 264 is not an odd number (false)
For (ii) 210 + 54 = 264 which is completely divisible by 4 (true)
For (iii) 54 + 28 < 50 (false

15. There are two series I and II given below, and both the series follow different patterns. A and B are missing terms of I & II respectively. Find the value of A and B, and answer the questions given below

I: 16, A, 10, 21, 85, 681
II: 44, 52, 64, 80, B, 124

Ques :  Which of the following statement/s is or are correct?
(i) A is a perfect square.
(ii) B = 10A
(iii) B ÷ (A+1) = 10

 

Correct Answer: (e) Only (i) and (iii)
Solution:

Pattern of series I:
16 × 0.5 + 1 = 9 = A
9 × 1 + 1 = 10
10 × 2 + 1 = 21
21 × 4 + 1 = 85
85 × 8 + 1 = 681

Pattern of series II:
44  52  64  80  B = 100  124
+8  +12  +16  +20  +24
+4  +4  +4  +4

For (i): A = 9 is perfect square (correct)
For (ii): 100 = 10 × 9
⇒ 100 = 90 (incorrect)
For (iii): 100 ÷ (9+1) = 10 (correct)

16. Find the value of 4A + 2B.

Correct Answer: (c) 236
Solution:Required value = 4 × 9 + 2 × 100
= 36 + 200 = 236

17. Which of the following statement/s is or are true?

(i) When 69 added in B, then the resultant becomes perfect square.
(ii) Value of A is a prime number.
(iii) 25 is a factor of (B+25).

Correct Answer: (b) Only (i) and (iii)
Solution:For (i): 100 + 69 = 169 is a perfect square (true)
For (ii): 9 is not a prime number (false)
For (iii): 100 + 25 = 125
⇒ 25 is factor of 125 (true)

18. Directions (18-21): The bar graph given below shows percentage distribution of total students (boys + girls) appeared in three exams A, B and C. The bar graph also shows percentage of students (boys + girls) passed in these three exams out of total students (boys + girls) appeared in particular exam. Read the data carefully and answer the questions given below.

Note: Total number of students appeared in three exams A, B and C = 900
Total number of students appeared in any exam = Students passed + Students did not pass.

Ques :  Find the average number of students who did not pass all three exams.

Correct Answer: (b) 156 
Solution:

Total students (boys + girls) appeared in exam A
= 900 × 20/100 = 180

Total students (boys + girls) appeared in exams B
= 900 × 50/100 = 450

Total students (boys + girls) appeared in exam C
= 900 − (180 + 450) = 270

Total students (boys + girls) passed in exam A
= 180 × 50/100 = 90

Total students (boys + girls) passed in exam B
= 450 × 40/100 = 180

Total students (boys + girls) passed in exam C
= 270 × 60/100 = 162

Total number of students who did not pass the exam A = 180 − 90 = 90
Total number of students who did not pass the exam B = 450 − 180 = 270
Total number of students who did not pass the exam C = 270 − 162 = 108

Required average = (90 + 270 + 108) / 3 = 468 / 3 = 156

19. Which of the following statement/s is or are correct?

I. Total number of students who did not pass the exam B are multiple of 9.

II. Total students who passed the exam A & B together > Total students who passed the exam B & C together

III. 50% of students who did not pass the exam A are equal to 1/6th of number of students who did not pass the exam B.

Correct Answer: (c) Only I and III
Solution:

For I. Total number of students who did not pass the exam B = 450 − 180 = 270
And 270 is multiple of 9 (correct)

For II. 90 + 180 < 180 + 162 (incorrect)

For III. 90/2 = 270/6
⇒ 45 = 45 (correct)

20. The average number of students passed in exam A, B and D is 150, and 70% of total students appeared in exam D are not pass the exam. If boys and girls who did not pass the exam D are equal and girls who passed the exam D are 40% of students who passed exam B, then find the total boys who appeared in exam D.

Correct Answer: (d) 318 
Solution:

Total students who passed the exam D
= 150 × 3 − (90 + 180) = 180

Total students who did not pass the exam D
= 180 × 70/30 = 420

Total boys who did not pass the exam D = 420/2 = 210

Total boys who passed exam D = 180 − 180 × 40/100
= 180 − 72 = 108

Required number = 210 + 108 = 318