BANK & INSURANCE (SBI PO MAINS 2025) MOCKTEST 2

The pattern of the series:
16X, 48000, 16000, 4000, Y, 133 1/3

16X → 48000 → 16000 → 4000 → Y → 400/3

× 1/2 → × 1/3 → × 1/4 → × 1/5 → × 1/6

16X × 1/2 = 48000
16X = 96000
X = 6000

4000 × 1/5 = Y
800 = Y

Required value = X/3 − 1.5Y
= 6000/3 − 1.5(800)
= 2000 − 1200
= 800

x² − 6x + 9 = 0
x² − 3x − 3x + 9 = 0
x = 3, 3
n = 3

The pattern of the series:
n, (n+1), (n+2)², ((n+1)³ − 2³), ((3x)² + 11), m

3, 4, 25, 56, 92, m

1, 21, 31, 36, 38.5

20 → 10 → 5 → 2.5
÷2 → ÷2 → ÷2

m = 92 + 38.5

m = 130.5

Required value = n × (m − 30.5) = 3 × (130.5 − 30.5)
= 3 × 100
= 300

Given,
5x + 4.5x + 27 + 10x − 18 = 360
19.5x = 351
x = 18

Degree of total number of tires (bus + truck) manufactured in April = 90 degree
Degree of total number of tires (bus + truck) manufactured in May = 108 degree
Degree of total number of tires (bus + truck) manufactured in June = 162 degree

Let the total number of tires (bus + truck) manufactured all three months together be 180a

The ratio of bus tires manufactured and truck tires manufactured in May = (18 − 4) : 11
= 14 : 11

The number of bus tires manufactured in May
= 180a × 108/360 × 14/25 = 30.24a

The number of bus tires sold in May = 30.24a × 75/100
= 22.68a

The number of bus tires unsold in May = 30.24a − 22.68a = 7.56a

Given, 7.56a = 21
a = 21/7.56

The total number of tires (bus + truck) manufactured all three months together
= 180 × 21/7.56 = 500

I. Total number of tires (bus + truck) manufactured in June > 225

Total number of tires (bus + truck) manufactured in June
= 500 × 162/360 = 225

It is incorrect.

II. Total number of truck tires manufactured in May < 68

Total number of truck tires manufactured in May
= 500 × 108/360 × 11/25 = 66

It is correct.

III. Total number of unsold truck tires in May is multiple of 11

Total number of unsold truck tires in May
= 500 × 108/360 × 11/25 × 50/100 = 33

It is correct.

The total number of truck tires manufactured in April
= 4x + 3 = 4(18) + 3 = 75

The total number of bus tires manufactured in April
= 75 × 2/3 = 50

Let the total number of tires (bus + truck) manufactured all three months together be 180a

180a × 90/360 = (75 + 50)
45a = 125
a = 125/45

The total number of tires (bus + truck) manufactured all three months together = 180a = 500

Quantity I: Total number of tires (bus + truck) manufactured in June = 500 × 162/360 = 225

Quantity II: Total number of bus tires and truck tires together sold in April
= 50 × 60/100 + 75 × 80/100 = 30 + 60 = 90

So, Quantity I > Quantity II

From I:
Total number of tires (bus + truck) manufactured in July = 20x = 20 (18) = 360
Total number of tires (bus + truck) manufactured in June = 360 × 100/80 = 450
Total number of tires (bus + truck) manufactured in May = 450 × 108/162 = 300

From II:
Total number of tires (bus + truck) sold in May = 192

Both statements together
Total number of tires (bus + truck) manufactured in May = 300
Total number of tires (bus + truck) sold in May = 192
Total number of tires (bus + truck) unsold in May = 300 − 192 = 108

We have no data about total number of bus tires or truck tires.
So, neither I nor II.

Total number of bus tires sold in April = 90
Total number of unsold truck tires in April = 2.5x = 2.5(18) = 45
Total number of bus tires manufactured in April = 90 × 100/60 = 150
Total number of truck tires manufactured in April = 45 × 100/20 = 225
Total number of tires (bus + truck) manufactured in April = 150 + 225 = 375

Total number of tires (bus + truck) manufactured in June = 375 × 162/90 = 675
Total number of tires (bus + truck) manufactured in May = 375 × 108/90 = 450

We have no data about the total number of bus tires or truck tires in May.
So, can’t be determined.

Let the total number of tires (bus + truck) manufactured all three months together be 180a

Given,
180a × 162−90 / 360 = (x+2)²
36a = 400
a = 400/36

The total number of tires (bus + truck) manufactured all three months together = 180a = 2000

The total number of tires (bus + truck) manufactured in May = 2000 × 108/360 = 600

Let the number of bus tires manufactured in May be P

And the number of truck tires manufactured in May = 600 − P

ATQ,
P × 75/100 − (600 − P) × 1/2 = 120
0.75P − 300 + 0.5P = 120
1.25P = 420
P = 336

The number of bus tires manufactured in May = 336
And the number of truck tires manufactured in May = 600 − 336 = 264

Total number of unsold tires (bus + truck) in May
= 336 × 25/100 + 264 × 1/2 = 84 + 132 = 216

In 2021
Let total number of students registered be 100x
Total number of students appeared = 90x
Total number of students did not appear = 10x

In 2022
Total number of students registered = 90x × 75/100 = 67.5x

In 2023
Total number of students did not appear = 20/100 × 67.5 = 13.5x

Total number of students not qualified in the exam in 2021 = 162
Total number of students did not appear in the exam in 2021 = 162 × 100/270 = 60
10x = 60
x = 6

Total number of students registered in the exam in 2022 = 67.5 (6) = 405
Total number of students did not appeared in 2023 = 20/100 × 405 = 81
Total number of students registered in the exam in 2023 = 81 + 190 = 271

13.5x − 10x = 14
x = 4

Total number of students registered in 2021 = 100x = 400
Number of students did not appeared 2022 = 67.5(4) − 140 = 130
Required average = (400 + 130)/2 = 265