Calendar (SSC REASONING)

Total Questions: 78

71. The birth date of Viaan is 9 March 2002. Find the day of the week on that day. [SSC CHSL 26/05/2022 (Evening)]

Correct Answer: (a) Saturday
Solution:Formula for calculating day of any date 0 = sunday, 1 = monday.... 6 = saturday A = century code (4,2,0,6 for remainder 1,2,3,0)dividing by first two digit of the year by 4 B = last two digits of year C = number of leap years fallen in that century before that date. D = month code (respective code of the months are 0,3,3,6,1,4,6,2,5,0,3,5) E = date Day = remainder of (A + B + C + D + E) when divided by 7. A = 6 , B = 02 , C = 0, D= 3 , E = 9
Day = (6 + 02 + 0 + 3 + 9)/7 = 20/7 Remainder = 6 ⇒ The day is Saturday

72. If 12 January 2019 was on Monday, what was the day on 14 December 1917? [SSC CHSL 07/06/2022 (Morning)]

Correct Answer: (d) Sunday
Solution:Number of odd days from 14 December 1917 to 14 December 2017 = 6 Number of odd days from 14 December 2017 to 14 December 2018 = 1 Number of odd days from 14 December 2018 to 12 January 2019 = 17 + 12 = 29 odd days Total no. of odd days = 6 + 1 + 29 = 36 odd days or 1 odd days The day on 14 December 1917 :- Monday − 1 = Sunday

73. What was the day of the week on 17 April 2014 ? [SSC CGL 16/08/2021 (Morning)]

Correct Answer: (c) Thursday
Solution:Formula for calculating day of any date 0 = sunday, 1 = monday …. 6 = saturday A = century code (4,2,0,6 for remainder 1,2,3,0 respectively); where remainder = Dividing the first two digit of the year by 4 B = last two digits of the year C = number of leap years in that century before that date. D = month code (respective code of the months from start to last are 0,3,3,6,1,4,6,2,5,0,3,5)

For ex June code is 4 , December is 5 and so on. , E = Date Day = Remainder of (A + B + C + D + E) when divided by 7. Using formula for 17 April 2014, A = 6, B = 14, C = 3, D = 6, E = 17 A + B + C + D + E = 46 46 divided by 7 gives remainder as 4. 4 means Thursday

74. What was the day of the week on 10 June 2011 ? [SSC CGL 18/08/2021 (Afternoon)]

Correct Answer: (c) Friday
Solution:Using formula for 10 June 2011 A = 6, B = 11, C = 2, D = 4 and E = 10 A + B + C + D + E = 33 33 divided by 7 gives 5 as remainder 5 means Friday.

75. What was the day of the week on 22 February 2012 ? [SSC CHSL 04/08/2021 (Afternoon)]

Correct Answer: (b) Wednesday
Solution:Formula for calculating day of any date 0 = sunday, 1 = monday …. 6 = saturday A = century code (4,2,0,6 for remainder 1,2,3,0 respectively); where remainder = Dividing the first two digit of the year by 4 B = last two digits of the year C = number of leap years in that century before that date. D = month code (respective code of the months from start to last are 0,3,3,6,1,4,6,2,5,0,3,5) For ex June code is 4 , December is 5 and so on. , E = Date Day = Remainder of (A + B + C + D + E) when divided by 7. For 22 February 2012, A = 6, B =12, C = 2, D = 3 and E = 22 A + B + C + D + E = 6 + 12 + 2 + 3 + 22 = 45 On dividing 45 by 7 we get 3 as remainder. ⇒ 3 means Wednesday.

76. If 31 August 2008 was Sunday, then what was the day of the week on 30 August 2012 ? [SSC CHSL 09/08/2021 (Afternoon)]

Correct Answer: (c) Tuesday
Solution:As we know, a non-leap year has 1 odd day. So, 31 August 2009 = Monday 31 August 2010 = Tuesday 31 August 2011 = Wednesday 31 August 2012 = Friday(as 2012 is a leap year) So, 30 August 2012 is Thursday.

77. If 18 October 2006 was Wednesday, then what was the day of the week on 17 October 2000 ? [SSC CPO 23/11/2020 (Morning)]

Correct Answer: (a) Tuesday
Solution:Number of odd days from 17 October 2000 to 17 October 2006 = 1 + 1 + 1 + 2 + 1 + 1= 7 odd day From 17 Oct. 2006 to 18 Oct. 2006 = 1 odd Total odd days = (7 + 1)/7 = 1 odd days Required Day = Wednesday − 1 = Tuesday

78. What was the day of the week on 14ᵗʰ March 2010 ? [SSC CPO 24/11/2020 (Morning)]

Correct Answer: (c) Sunday
Solution:Formula for calculating day of any date 0 = sunday, 1 = monday …. 6 = saturday A = century code ( 4 , 2 , 0 , 6 for remainder 1 , 2 , 3 , 0 respectively); where remainder = Dividing the first two digit of the year by 4 B = last two digits of the year C = number of leap years in that century before that date. D = month code (respective code of the months from start to last are ( 0 , 3 , 3 , 6 , 1 , 4 , 6 , 2 , 5 , 0 , 3 , 5 ) For ex June code is 4 , December is 5 and so on. E = Date Day = Remainder of (A + B + C + D + E) when divided by 7. For 14 March 2010, A = 6, B = 10, C = 2, D = 3, E = 14 A + B + C + D + E = 35 35 divided by 7 gives remainder as 0. 0 means Sunday.