NTA UGC NET/JRF Exam, December-2019 (Electronic Science)Total Questions: 10031. What is the absolute potential at a point 'p' which is 2 m from a point charge Q = +5µC and the work required to move a + 8 nC charge from infinity to P? Assume ∈ᵣ = 1:A. 22 KV, 176 µJB. 23 KV, 184 µJC. 23.5 KV, 188 μJD. 22.5 KV, 180 μJCorrect Answer: D. 22.5 KV, 180 μJ32. If the Poynting vector or power density of a TEM wave = 79.6 W/m² in a loss less medium (o = 0) with ∈ᵣ = 4, then the magnitude of Electric field is:A. 86.62 Vm⁻¹В. 173.23 Vm⁻¹C. 122.5 Vm⁻¹D. 43.30 Vm⁻¹Correct Answer: C. 122.5 Vm⁻¹33. Evaluate radiation resistance of a Hertzian dipole as radiating element having length L = 1 m at f = 30 MHz with uniform current distribution:Α. 9 ΩΒ. 10 ΩC. 5 ΩD. 8 ΩCorrect Answer: D. 8 Ω34. The fields around an antenna may be divided into two principal regions i.e. Fresnel zone and Fraunhofer zone. If L is the maximum dimension of the antenna and A is wavelength, then radius of the Fresnel-Fraunhofer boundary sphere is:A.B.C.D.Correct Answer: C.35. Standing wave envelope for reflected wave is equal to half the incident wave amplitude (Eᵣ = 0.5Eᵢ). The Voltage Standing Wave Ratio (VSWR) of the wave shall be:A. 1/3B. 2C. 3D. 1/2Correct Answer: C. 336. The Figure of Merit in DSB-SC system is:A.B.C.D.Correct Answer: B.37. The frequency range for satellite communication is:A. 1 KHz - 100 KHzВ. 100 KHz – 1 MHzC. 10 MHz - 30 MHzD. 1 GHz - 30 GHzCorrect Answer: D. 1 GHz - 30 GHz38. The cladding which surrounds the optical fibre core:A. is used to reduce optical interferenceB. is used to protect the fibreC. acts to help guide the light in the coreD. ensure that the refractive index remains constantCorrect Answer: C. acts to help guide the light in the core39. A binary data sequence 11001110 is applied to 16-ary PSK modulator system for transmission. The bit duration is 1 µ sec. The transmission bandwidth of 16-ary PSK is:A. 1 MHzВ. 0.67 MHzC. 0.5 MHzD. 0.37 MHzCorrect Answer: C. 0.5 MHz40. A TDM link has 24 signals and each channel is sampled 8000 times/sec. Each sample is represented by 8 binary bits and it contains an additional bit for synchronization. The total bit rate made from the TDM link is:A. 1600 K bits/secВ. 1728 K bits/secC. 1826 K bits/secD. 2056 K bits/secCorrect Answer: В. 1728 K bits/secSubmit Quiz« Previous12345678910Next »