Solution:1/(1×2) + 1/(2×3) + ………. + 1/(99×100)
= 1/2 + 1/6 + 1/12 + ………. + 1/(99×100)
= 99/100 = 0.99
Short Tricks :-
Sum = 1/((n-1)d) × { (1/k) - (1/L) }
Where,
n = no. of terms in denominator
d = difference between the terms
k = first term of first denominator
L = last term of last denominator
Required Sum = 1/((2–1)1) × { (1/1) – (1/100) }
= {99/100} = 0.99