Number System-Railway Maths Part VIIITotal Questions: 5011. Find the units digit in the product of (127)¹⁵³ × (341)⁸⁹. [RRB NTPC 19/03/2021 (Evening)](a) 5 (b) 3 (c) 4 (d) 7Correct Answer: (d) 7Solution:(127)¹⁵³ × (341)⁸⁹ 153 ÷ 4 = Remainder = 1 unit digit = 7¹ × 1 = 712. Find the least multiple of 13, which on dividing by 4, 5, 6, 7, and 8 leaves a remainder 2 in each case. [RRB NTPC 19/03/2021 (Evening)](a) 2824(b) 2522(c) 2142(d) 2422Correct Answer: (b) 2522Solution:LCM of (4, 5, 6, 7, 8) = 840 The number should be multiple of 13 and remainder = 2, it will in the form of 840k + 2, Put k = 3 840 × 3 + 2 = 252213. How many 3-digit numbers are divisible by 7? [RRB NTPC 21/03/2021 (Morning)](a) 126(b) 128(c) 125(d) 130Correct Answer: (b) 128Solution:3 digits number which is divisible by 7 = 105, 112, 119..., 994 aₙ = a + (n−1 )d Where, First term = a = 105, Common difference = d = 112 - 105 = 7⇒ 994 = 105 + (n - 1)(7)⇒ 994 = 105 + 7n - 7⇒ 896 = 7n⇒ n = 128 14. 6⁶¹ + 6⁶² + 6⁶³ + 6⁶⁴ + 6⁶⁵ is completely divisible by: [RRB NTPC 21/03/2021 (Morning)](a) 17(b) 13(c) 11 (d) 15Correct Answer: (d) 15Solution:6⁶¹ + 6⁶² + 6⁶³ + 6⁶⁴ + 6⁶⁵ = 6⁶¹ (1 + 6 + 6² + 6³ + 6⁴) = 6⁶¹ (1 + 6 + 36 + 216 + 1296) = 6⁶¹ (1555) = 6⁶⁰ (9330) = 6⁶⁰ (622 × 15) so, it is divisible by 1515. Find the least number that, when divided by 72, 80 and 88, leaves the remainder 52, 60, 68 respectively. [RRB NTPC 21/03/2021 (Morning)](a) 7940(b) 7900(c) 7930(d) 7920Correct Answer: (b) 7900Solution:Here (72 - 52) = 20, (80 - 60) = 20 and (88 - 68) = 20Required number (LCM of 72, 80 and 88) - 20 = 7920 - 20 = 790016. How many numbers between 100 and 300 are divisible by 7? [RRB NTPC 21/03/2021 (Evening)](a) 30(b) 28(c) 27 (d) 29Correct Answer: (b) 28Solution:Total numbers between 100 and 300 = 200Now 200/7 =28 (quotient) 28 numbers are divisible by 7.17. Kunal was asked to find 5/6 times of a number. He multiplied it by 6/5. As a result, he got an answer which was more than the correct answer by 572. The number was: [RRB NTPC 21/03/2021 (Evening)](a) 2860(b) 5720(c) 1560(d) 2160Correct Answer: (c) 1560Solution:18. The greatest number of four digits which is divisible by 5, 35, 39 and 65 is: [RRB NTPC 21/03/2021 (Evening)](a) 9994(b) 9505(c) 9055(d) 9555Correct Answer: (d) 9555Solution:Largest number of four digit = 9999LCM of (5, 35, 39, 65) = 1365When we divide 9999 by 1365, we get remainder = 444Now, 9999 - 444 = 955519. Which of the following is a rational number? [RRB NTPC 27/03/2021 (Morning)](a) (√2 + √5)² (b) 2 + √5(c) 2 - √5(d) (√2 + 1/√8)²Correct Answer: (d) (√2 + 1/√8)²Solution:It is a rational number.20. Find the greatest number which divides 285 and 1249 leaving remainders 9 and 7 respectively. [RRB NTPC 27/03/2021 (Morning)](a) 140(b) 138 (c) 130(d) 141Correct Answer: (b) 138 Solution:285 - 9 = 2761249 - 7 = 1242HCF of 276 and 1242 = 138Submit Quiz« Previous12345Next »