Solution:The number of 4 digit integers greater than 6000 formed using the digits 3,5,6,7 and 8 without repetition is = 3×4×3×2 = 72.
The number of 5 digit integers greater than 6000 formed using the digits 3, 5, 6, 7 and 8 without repetition is 5! = 120
Hence, total number of integers greater than 6000 that can be formed using the digits 3, 5, 6, 7 and 8 without repetition is = 120+72 = 192.