RBI OFFICER GRADE ‘B’ PHASE-I EXAM Held on : 21.11.2015(Part-I)

Total Questions: 50

1. Study the following information carefully and answer the given questions.

Data regarding number of graduates studying various courses in University A and that in University B in the year 2001.
(Note: Universities A and B offer courses in six courses only. namely Commerce, Science, Engineering. Arts, Management and Law.)

• In University A, graduates in commerce, science and engineering together constituted 60% of the total number of graduates (in all the given six courses together). Graduates in Arts, Management and Law were 1300, 1440 and 860 respectively. Commerce graduates were 25% more than that of engineering graduates. Management graduates were 20% less than that of science graduates.
• In University B. Commerce graduates were 10% less than the Commerce graduates in University A.
• In University B. Management graduates were 900 and they constituted 12% of the total number of graduates (in all the given six courses together). Also management graduates were 40% less than that of science graduates. Total number of graduates in engineering and Arts together were double the total number of graduates in management and law together. The ratio of engineering and arts graduates is 3: 5 respectively.

What is the difference between the total number of graduates in management and law together in University A and that in the same courses together in University B?

Correct Answer: (2) 900
Solution:In university A,
Arts graduates 1300
Management graduates 1440
Law graduates 860
Science graduates





- 1500 = 3300 ... (ii)
By equation (ii) - (i),
3 Law = 3300 - 2800

Required difference
= 1440 + 860 - 900 - 500
= 900

2. 3/4 th of the number of arts graduates in University A were females. If the number of female arts graduates in University A is less than that in University B by 175, what is the number of male arts graduates in University B?

Correct Answer: (3) 600
Solution:In university A,
Arts graduates 1300
Management graduates 1440
Law graduates 860
Science graduates





- 1500 = 3300 ... (ii)
By equation (ii) - (i),
3 Law = 3300 - 2800

Female Arts graduates in
university A = 3/ 1300 = 975
Female Arts graduates in university B
= 975 + 175 = 1150
Male Arts graduates
= 1750 - 1150 = 600

3. What is the respective ratio between the total number of graduates in engineering and commerce together in University A and that in the same courses together in University B?

Correct Answer: (5) 24 : 19
Solution:In university A,
Arts graduates 1300
Management graduates 1440
Law graduates 860
Science graduates





- 1500 = 3300 ... (ii)
By equation (ii) - (i),
3 Law = 3300 - 2800

Required ratio
= (1600 + 2000) : (1050 + 1800)
= 3600 : 2850 = 24 : 19

4. Number of science graduates in University B is what percent less than that in University A?

Correct Answer: (1) 16 ²⁄₃
Solution:In university A,
Arts graduates 1300
Management graduates 1440
Law graduates 860
Science graduates





- 1500 = 3300 ... (ii)
By equation (ii) - (i),
3 Law = 3300 - 2800

Required percent = 100
= = 16 ²⁄₃ %

5. Total number of graduates (in all the given six courses together) in University A, was what percent more than that in University B?

Correct Answer: (2) 20
Solution:In university A,
Arts graduates 1300
Management graduates 1440
Law graduates 860
Science graduates





- 1500 = 3300 ... (ii)
By equation (ii) - (i),
3 Law = 3300 - 2800

Required percent

6. In a village, 70% registered voters cast their votes in the election. Only two candidates (A and B) contested the election. A won the election by 400 votes. Had A received 12.5% less votes, the result would have been tie. How many registered voters are there in the village?

Correct Answer: (3) 4000
Solution:Votes received by A = x (let)
Votes received by B = x - 400
According to the question,

7. Area of a rectangle is 96 square metre. When the length of the same rectangle is increased by 6 metres and the breadth is decreased by 3 metres, then the area of the rectangle decreases by 30 square metres. What is the perimeter of a square whose sides are equal to the length of rectangle?

Correct Answer: (4) 64 m
Solution:Length of rectangle = x metre (let)
Its width = metre
According to the question,

x² - 192 = 4x
x² - 4x - 192 = 0
x² - 16x + 12x - 192 = 0
x(x - 16) + 12 (x - 16) = 0
(x + 12) (x - 16) = 0
x = 16 because x ≠-12
Perimeter of square = 4 16
= 64 metre

8. A vessel contains a mixture of milk and water in the respective ratio of 3:1. 32 litres of mixture was taken out and replaced with the same quantity of milk so that the resultant ratio between the quantities of milk and water in the mixture was 4:1 respectively. If 10 litres of mixture is again taken out from the vessel, what is the resultant quantity of water in the mixture? (in litres)

Correct Answer: (2) 30
Solution:Initial quantity of milk in the vessel = 3x litres
Initial quantity of water = x litres
In 32 litres of mixture,
Milk = 3/  32 = 24 litres
Water = 8 litres
According to the question,

∴ Required quantity of water
= 32 - 2 = 30 litres

9. Refer to the table and answer the given questions.

Data related to performance of 6 batsmen in a tournament :
Name of the batsmanNumber of matches played in the tournamentAverage runs scored in the tournamentTotal balls faced in the tournamentStrike rate in the tournament
M2256--
N18--153.6
O--900110
P-36120084
Q---140
R24511368-

Note :
(i) Strike rate = (Total runs scored/Total balls faced) 100
(ii) All the given batsmen could bat in all the given matches played by them. (iii) Few values are missing in the table (indicated by --). A candidate is expected to calculate the missing value, if it is required to answer the given question, on the basis of the given data and information.

If the runs scored by R in the last 3 matches of the tournament are not considered, his average runs scored in the tournament will decrease by If the runs scored by R in the 22nd and 23rd match are below 140 and no two scores among these 3 scores are equal, what is the minimum possible runs scored by R in the 24th match?

Correct Answer: (1) 65
Solution:Total runs scored by R in
the last three matches
= 24 51 - 21 42
= 1224 - 882 = 342
Maximum runs possible
in 22nd match = 139
Maximum runs possible in 23 rd match = 138
Minimum score in 24th match
= 342 - 139 - 138
= 65

10. The respective ratio between total number of balls faced by O and that by Q in the tournament is 5 : 3. Total number of runs scored by Q in the tournament is by what percent less than the total number of runs scored by O in the tournament?

Correct Answer: (5) 23 ⁷⁄₁₁
Solution:Balls faced by batsman O
= 900
Balls faced by batsman Q

= = 23 ⁷⁄₁₁