Trigonometry (Railway Maths) (Part – I)Total Questions: 5031. In any triangle ABC, a + b + c = 2s with usual notation, then sin(A/2) =? [NTPC CBT - I 07/01/2021 (Evening) ](a)(b)(c)(d)Correct Answer: (b)Solution:32. Value of A for the equation: [NTPC CBT - I 07/01/2021 (Evening) ]tanA + tan2A + tan3A = tanA tan2A tan3A is:(a) 5π/6(b) π/3, 2π/3(c) 2π/3(d) π/3Correct Answer: (b) π/3, 2π/3Solution:33. If A , B and C are the interior angles of a Δ ABC , simplify [NTPC CBT - I 10/01/2021 (Morning) ](a) 1(b) 2(c) 0(d) Not definedCorrect Answer: (a) 1Solution:34. If x = rsinAcosC , y = rsinAsinC, and z = rcosA, then find the value of x² + y² + z². [NTPC CBT - I 11/01/2021 (Morning) ](a) r²(b) 2r(c) 2r²(d) 0Correct Answer: (a) r²Solution:35. If sin(A + B) = √3/2 and cos(A - B) = √3/2, then which of the following will be possible values of A and B? [NTPC CBT - I 12/01/2021 (Morning) ](a) A = 10°, B = 45°(b) A = 50°, B = 10°(c) A = 45°, B = 30°(d) A = 45°, B = 15°Correct Answer: (d) A = 45°, B = 15°Solution:36. If sin(3x - 20)° = cos(20 - 3y)°, then value of x - y will be: [NTPC CBT - I 12/01/2021 (Evening) ](a) 20°(b) 60°(c) 30°(d) 45°Correct Answer: (c) 30°Solution:sin(3x - 20)° = cos (20 - 3y)° ⇒ cos(90° - (3x - 20°)) = cos (20 - 3y)° ⇒ 110° - 3x = 20° - 3y ⇒ 90° = 3x - 3y ⇒ 3 (x - y) = 90° ⇒ x - y = 30°37. If acosθ - bsinθ = c, then find the value of asinθ + bcosθ. [NTPC CBT - I 16/01/2021 (Morning) ](a)(b)(c)(d)Correct Answer: (b)Solution:38. What is the value of the following expressions? 1 + secθ + tanθ / 1 + secθ - tanθ [NTPC CBT - I 18/01/2021 (Evening) ](a)(b)(c)(d)Correct Answer: (c)Solution:39. The value of 4 cos(π/6 − α) sin(π/3 − α) is equal to: [NTPC CBT-I 18/01/2021 (Evening)](a) 3 + sin²α(b) 3 + 4 sin²α(c) 3 − sin²α(d) 3 − 4 sin²αCorrect Answer: (d) 3 − 4 sin²αSolution:40. If tanθ = x − 1/(4x), then secθ − tanθ is equal to: [NTPC CBT-I 19/01/2021 (Morning)](a) 2x or 1/(2x)(a) 2x or 1/(2x)(c) −2x or −1/(2x)(d) −2x or 1/(2x)Correct Answer: (d) −2x or 1/(2x)Solution:Submit Quiz« Previous12345Next »