UGC NTA NET/JRF Exam, Environmental Sciences, September-2024

Total Questions: 100

11. Primary producers convert only about 1% of energy available to them to Net Primary Production. There is trophic efficiency of 10% for each link in the food chain. What would be the energy available to tertiary consumers in an idealized pyramid of energy when 1,000,000 J of sunlight is available

Correct Answer: D. 10 J
Solution:

Primary producers, such as green plants, capture only about 1% of the total incoming solar energy. In this problem, 1,000,000 J of sunlight is available. The 1% that is converted to net primary productivity (NPP) amounts to 1,000,000 × 0.01 = 10,000 J.

At each successive trophic level (primary consumer, secondary consumer, tertiary consumer), the ecological (trophic) efficiency is assumed to be 10%.

Thus, a primary consumer would receive 10% of 10,000 J = 1,000 J, a secondary consumer would get 10% of that = 100 J, and finally the tertiary consumer would receive 10% of 100 J = 10 J.

12. The process of destabilisation of colloids. by altering surface properties in order to allow the individual particles to combine into larger ones is best referred as:

Correct Answer: C. Coagulation
Solution:

Destabilization of colloidal particles by neutralizing or reducing the repulsive forces among them is a fundamental step in water and wastewater treatment known as coagulation.

Chemical coagulants such as aluminum sulphate (alum) or ferric salts are added so that colloidal particles lose their surface charge and can then stick together. Once the particles are destabilized, gentle mixing or flocculation helps them form larger aggregates or flocs, which can then be removed by settling or other means.

The key word in the question is "destabilisation," which is distinct from flocculation: coagulation is the chemical charge-neutralization phase, while flocculation is the subsequent physical aggregation.

13. Which of the following statements are TRUE for the situations of testing of statistical hypothesis:

Choose the most appropriate answer from the options given below:

Correct Answer: D. (a) and (e) only
Solution:

14. Match the List-I with List-II.

List-I (Conditions)List-II (Plume Behaviour)
(a) Inversion below, lapse aloftI. Fumigation
(b) Strong lapse conditionII. Lofting
(c) Lapse below, inversion aloftIII. Looping
(d) Weak lapse below, inversion aloftIV. Trapping

Choose the correct answer from the options given below:

Option(a)(b)(c)(d)
A.IIIIIIIV
B.IIIIIIIV
C.IIIIIIIV
D.IIIIIIVI
Correct Answer: B.
Solution:

Various thermal structures of the atmosphere create characteristic plume behaviours:

(a) Inversion below and lapse (unstable or neutral) aloft → Lofting (II). A stable layer beneath the stack prevents the plume from moving downward, while the lapse region above allows the plume to rise and disperse upward.

(b) Strong lapse condition → Looping (III). Under highly unstable (super-adiabatic) conditions, the plume rises and sinks in oscillating loops due to strong vertical mixing.

(c) Lapse below and inversion above → Fumigation (I). The plume can move downward into the unstable air but is capped above by a stable inversion, forcing the pollutants downward.

(d) Weak lapse below and inversion aloft → Trapping (IV). In this scenario, the upper stable layer combines with a near-stable lower layer, and the plume remains confined in a thin vertical layer, effectively "trapping" the pollutants.

15. Which of the following air pollution-control/particle-collection devices uses the force of gravity to aid in collection of particles by exploiting their terminal velocity?

Correct Answer: B. Elutriators
Solution:

Elutriators separate particles from an air stream primarily by gravitational settling through a vertical chamber. The device slows down the flow enough that particles with sufficient terminal velocity will drop out of the gas stream.

Unlike electrostatic precipitators (which use electrostatic forces), bag houses (which use filtration), or super saturators (which involve condensation effects), elutriators exploit gravity as the main separating force. This principle relies on each particle's settling velocity, which depends on factors like size, shape, and density.

16. Match the List-I with List-II.

List-I (Plastic)List-II (Application)
(a) PETE (Polyethylene Terephthalate)I. Straw
(b) HDPE (High-Density Polyethylene)II. Pharmaceutical bottles
(c) PP (Polypropylene)III. Soft drink bottles
(d) PS (Polystyrene)IV. Milk bottles

Choose the correct answer from the options given below:

Option(a)(b)(c)(d)
A.IIIIVIII
B.IIIIVIII
C.IVIIIIII
D.IIIIIIIV
Correct Answer: B.
Solution:

Different types of plastics have characteristic applications due to their physical and chemical properties.

(a) PETE (Polyethylene terephthalate) → Soft drink bottles (III). Because of PETE's clarity, strength, and gasbarrier properties, it is widely used in carbonated beverage containers.

(b) HDPE (High Density Polyethylene)→  Milk bottles (IV). Its high strength-todensity ratio and chemical resistance make it well-suited for milk jugs, detergent bottles, etc.

(c) PP (Polypropylene)→ Straw (I). Polypropylene has good rigidity, is relatively safe in contact with food/ beverages, and is easily moldable, making it common in straws and various caps.

(d) PS (Polystyrene) → Pharmaceutical bottles (II). Polystyrene can be used in certain rigid packaging applications, including some pharmaceutical or vitamin bottles and laboratory disposable ware.

17. Benzene, toluene, ethylbenzene and xylene, (BTEX) are common constituent of gasoline. Vapour pressure of pure liquids are respectively. 0.126, 0.0380, 0.0126 and 0.0117 at 25° C. Assuming equimolar mixture of these liquids obeys Raoult's law, which one of given will exert maximum partial pressure in the mixture

Correct Answer: C. Benzene
Solution:

18. What is the concentration of oxygen in the ambient atmosphere (on dry basis) at 0°C and 1 atm pressure in the unit of g/l?

Correct Answer: C. ~0.299 g/l
Solution:

19. Arrange the following in increasing order of O/C atomic ratio of a coalification path.

(a) Vitrinite
(b) Huminite
(c) Lignin
(d) Wood
(e) Cellulose
Choose the most appropriate answer from the options given below:

Correct Answer: A. (a), (b), (c), (d), (e)
Solution:

In coalification (the progressive transformation of plant material to coal), the O/C atomic ratio generally decreases as one goes to more mature stages.

Wood and cellulose have high O/C ratios, while the macerals in coal (like huminite and vitrinite) show progressively lower O/C ratios as rank increases.

The question asks for the increasing order of O/C ratio, which means from smallest to largest. Among the listed materials: Vitrinite has the lowest O/C ratio, followed by huminite, then lignin, then wood, and finally cellulose has one of the highest O/С ratios.

So the sequence in ascending order is Vitrinite (a) < Huminite (b) < Lignin (c) < Wood (d) < Cellulose (e).

20. Beak depths in two species of Galapagos Finches, Geospiza Fuliginosa and Geospiza fortis are similar in allopatric populations but have diverged in sympatric populations. This is an example of:

Correct Answer: C. Character displacement
Solution:

When two closely related species (such as Geospiza fuliginosa and Geospiza fortis) occur in allopatric populations (separate geographic locations), their beak depths are quite similar.

However, in sympatric populations (where they cooccur), competition for food resources can drive evolutionary divergence in beak morphology—a phenomenon called character displacement.

It is an adaptation that reduces niche overlap and direct competition by favouring individuals that exploit different food types or feeding strategies. This allows both species to coexist by minimizing direct resource competition.